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Description=Площа(AEF)+Площа(FCD)=Площа(BEFD)~~Це можна довести, якщо використати такі 2 ствердження:~~1. Середня лінія трикутника поділяє його на дві фігури,~~площі яких відносяться як 1:3~~2. Площа(BED)=Площа(FED)~~
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Caption=Нехай задано довільний трикутник ABC,~~D та E - середини сторон BC та AB відповідно.~~F - довільна точка на AC.~~~~Що можна сказати про площі трикутників~~AEF і FCD та чотирикутника BEFD?~~~~Що буде, коли F переміщувати по AC?
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